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90/x^2=40
We move all terms to the left:
90/x^2-(40)=0
Domain of the equation: x^2!=0We multiply all the terms by the denominator
x^2!=0/
x^2!=√0
x!=0
x∈R
-40*x^2+90=0
We add all the numbers together, and all the variables
-40x^2+90=0
a = -40; b = 0; c = +90;
Δ = b2-4ac
Δ = 02-4·(-40)·90
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-40}=\frac{-120}{-80} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-40}=\frac{120}{-80} =-1+1/2 $
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